For this problem we have the following two inequalities given:
[tex]x+2y\ge4\text{, y}-2x<0[/tex]And we want to find the point of solution to the system of inequalities and for this case we can work with equations
[tex]x+2y=\text{4 (1) }[/tex][tex]y-2x=\text{ 0 (2)}[/tex]If we solve for x from equation (1) we got:
[tex]x=\text{ 4}-2y\text{ (3)}[/tex]And replacing equation (3) into equation (2) we got:
[tex]y-2(4-2y)=\text{ 5y}-8=\text{ 0}\rightarrow y=\text{ }\frac{8}{5}=\text{ 1.6}[/tex]And solving for x we got:
[tex]x=\text{ 4}-(2\cdot1.6)\text{ = 0.8}[/tex]So then the intersection point between the two lines is (0.8,1.6). If we analyze all the possible options we have this:
(1,2)