Question

24.A projectile is launched upward at an angle of 30° from thehorizontal with an initial velocity of 145 meters per second. Howfar does the projectile travel horizontally?(a) 1.86 x 10^3 m(b) 2.28 x 10^3 m(c) 4.55 x 10^3 m(d) 9.10 x 10^3 m

Answer 1

ANSWER:

(a) 1.86 x 10^3 m

STEP-BY-STEP EXPLANATION:

The movement that the projectile takes is a parabolic movement, therefore, the horizontal range is determined as follows:

$x=\frac{v^2_0\cdot\sin (2\theta)}{g}$

We know the initial velocity, the angle and the gravity, therefore, we replace and calculate the value of the horizontal distance:

$\begin{gathered} x=\frac{145^2\cdot\sin (2\cdot30)}{9.8} \\ x=1857.97\cong1.86\cdot10^3 \end{gathered}$

The horizontal distance is equal to approximately 1860 meters