Given data
*Kevin exerted a force is F = 165 N
*The given acceleration is
[tex]a=28.5m/s^2[/tex]The formula for the mass of the shot put is given as
[tex]m=\frac{F}{a}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} m=\frac{165}{28.5} \\ =5.78\text{ kg} \end{gathered}[/tex]Thus, the mass of the shot put is m = 5.78 kg