Question

The function $f(t) = 1600(0.93) ^{10t}$represents the change in a quantity over t decades. What does the constant 0.93 reveal about the rate of change of the quantity?

Answer 1

Given the function;

$f(t)=1600\cdot(0.93)^{10t}$

The function shows exponential decay with a rate of 0.93

So, the quantity will decrease each year with the rate of 0.93