For n= 1
[tex]A(1+1)=\frac{1}{2}A(1)[/tex]but A(1) = 4
[tex]A(2)\text{ = }\frac{1}{2}(4)\text{ = 2}[/tex]For n= 2
[tex]A(2+1)=\frac{1}{2}A(2)[/tex][tex]A(3)=\frac{1}{2}A(2)[/tex]But A(2) = 2
[tex]A(3)\text{ =}\frac{1}{2}(2)=\text{ 1}[/tex]Hence, the first three terms are;
4, 2, 1