First, let's calculate the total amount of coins:
[tex]7+2+1=10[/tex]Since there are 7 pennies among the 10 coins, the probability of picking a penny is:
[tex]P_1=\frac{7}{10}[/tex]Then, there will be 9 coins, from which only 1 is a dime, so the probability of the second pick being a dime is:
[tex]P_2=\frac{1}{9}[/tex]Now, to calculate the final probability, let's multiply both probabilities above:
[tex]\begin{gathered} P=P_1\cdot P_2 \\ P=\frac{7}{10}\cdot\frac{1}{9} \\ P=\frac{7}{90} \end{gathered}[/tex]Therefore the probability is 7/90.