Question

A dog, of mass 25.0 Kg, rides in an elevator. The elevator applies a force to the dog of 500N. Calculate:A. The net force acting on the dogB. The acceleration of the elevator.

Answer 1

Answer:

a) The net force acting on the dog = 549 N

b) The acceleration of the elevator = 20 m/s²

Explanation:

The mass of the dog, m = 25.0 kg

Force applied to the dog, F = 500 N

Acceleration due to gravity, g = 9.8 m/s²

A) The net force acting on the dog in the elevator is:

$\begin{gathered} F_{\text{Net}}=mg+F \\ F_{\text{Net}}=5(9.8)+500 \\ F_{\text{Net}}=49+500 \\ F_{\text{Net}}=549N \end{gathered}$

B) Calculate the acceleration of the elevator

F = ma

500 = 25a

a = 500/25

a = 20 m/s²