Question

5. Consider the equation 3a + 0.1n = 123. If we solve this equation for n,which equation would result? *A. 0.1n = 123 - 3aB. n = 123 - 3a - 0.1C. n = 1,230 - 30aD. (3a - 123)/0.1 = n

Answer 1

The given equation is

$3a+0.1n=123$

Rearranging,

0.1n=123-3a .......... (1)

On furthur rearranging,

$n=\frac{123-3a}{0.1}=1230-30a$

The equation that we get whilw solving for n is:

C.n=1230-30a