The given quantity is
[tex]1.2\ast10^{-6}m[/tex]The general conversion rules are
[tex]\begin{gathered} 1\operatorname{cm}=10\operatorname{mm} \\ 1m=100\operatorname{cm} \\ 1\operatorname{km}=100m \end{gathered}[/tex][tex]\begin{gathered} So \\ 1.2\ast10^{-6}m=1.2\ast10^{-6}\ast1m=1.2\ast10^{-6}\ast100\operatorname{cm} \\ =1.2\ast10^{-6}\ast100\ast10\operatorname{mm}=1.2\ast10^{-3}\operatorname{mm} \end{gathered}[/tex]The answer is option c.