Question

I don’t understand i need help and it’s time sensitive i have 3 mins

Answer 1

From the given image,

$\cos(\theta)=\frac{9}{41}$

Recall the trigonometric identity:

$\sin^2(\frac{\theta}{2})=\frac{1-\cos(\theta)}{2}$

Substitute cos (θ) = 9/41 into the equation:

$\sin^2(\frac{\theta}{2})=\frac{1-\frac{9}{41}}{2}=\frac{41-9}{82}=\frac{32}{82}=\frac{16}{41}$

Therefore,

$\sin(\frac{\theta}{2})=\sqrt{\frac{16}{41}}=\frac{4\sqrt{41}}{41}$

Therefore, the required answer is:

sin(θ/2) = (4√41)/41

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