Question

Multiply.x²yx2 + 11x + 28y2+ 2x - 8хуStep 1Factor the denominator of the first fraction and the numerator of the second fraction.(x + 4)(x + 4) (x - 2)хбузI-2X ++4Step 2Multiply*?y4(x + 4)(x + 7)(x + 4)(x + 4 x - 2)xyD|)(x+4)=93Submit Skip (you cannot come back)

Answer 1

Given:

$\frac{x^2y^4}{x^2+11x+28}\cdot\frac{x^2+2x-8}{x^6y^3}$

Step 1

Factor the denominator of the first fraction and the numerator of the second fraction.

$\frac{x^2y^4}{(x+4)(x+7)^{}}\cdot\frac{\mleft(x+4\mright)(x-2)}{x^6y^3}$

Step 2

Multiply

$\frac{x^2y^4}{\mleft(x+7\mright)(x+4)^{}}\cdot\frac{\mleft(x+4\mright)(x-2)}{x^6y^3}=\frac{x^2y^4(x+4)(x-2)}{(x+7)(x+4)x^6y^3^{}}$