Question 4:
The equation of the line:
[tex]y\text{ = -2x+1}[/tex]If the point (3, -5) lies on the line, when we substitute the x-value into the equation, we should have the given y-value.
Hence,
[tex]\begin{gathered} x\text{ = 3} \\ \text{Substitutitng:} \\ y=\text{ -2(3) + 1} \\ =\text{ -6 + 1} \\ =\text{ -5} \end{gathered}[/tex]We can conclude that the point (3, -5) lies on the line.
Question 5
Given expression:
[tex]=-y^2-2xy[/tex]Where:
x = -5 and y = 3:
Substituting we have:
[tex]\begin{gathered} =-3^2\text{ -2(-5)(3)} \\ =\text{ -9 +30} \\ =\text{ 21} \end{gathered}[/tex]Answer: 21