Question

Kayla was 36 in. tall at age 3. Today, at age 5, she is 42 in. tall.To the nearest percent, what is the percent of change in Kayla'sheight?O A. 2%OB. 8%O C. 14%O D. 17%

Answer 1

What we call percentage is basically this:

We have a number, let's call it 'a' ( a can be 1,2,100,423432, whatever you want!)

Then we divide a by 100 and called the result 1%, in other words:

$\begin{gathered} \frac{a}{100}=1\text{percent} \\ \Rightarrow100(\frac{a}{100})=100percent \end{gathered}$

This is basically what a percentage is

So, in our problem, a=42in, as this is the final Kayla's height:

Then, we want to know what percentage of 42in is equal to 42in-36in=6in (change in Kayla's height)

$\begin{gathered} x(\frac{42}{100})=6 \\ \Rightarrow x=(\frac{100}{42})\cdot6=14.3\text{ approx} \end{gathered}$

So, the difference in percentage is: 14.3% which is the option C