Question

I 3. Write the equation of the line that has a slope of -2/3 and passes through (-1,3).

Answer 1

To find the equation of a line we can use the following:

$y-y_1=m(x-x_1)$

Where m is the slope of the line and (x1, y1) is a point of the line.

Then, replacing m by -2/3 and (x1, y1) by (-1, 3), we get:

$\begin{gathered} y-3=-\frac{2}{3}(x-(-1)) \\ y-3=-\frac{2}{3}(x+1) \\ y-3=-\frac{2}{3}x-\frac{2}{3}\cdot1 \\ y=-\frac{2}{3}x-\frac{2}{3}+3 \\ y=-\frac{2}{3}x+\frac{7}{3} \end{gathered}$

Answer: y = (-2/3)x + (7/3)