Question

The diameter of a cylinder is 4 m. If the height is triple the radius, which is the closest to the volume of the cylinder?

Answer 1

Given:

There are given that the diameter of a cylinder is 4m.

Explanation:

The diameter of the cylinder is given 4 m.

Then,

We need to find the value for the radius.

So,

From the formula of the radius:

$r=\frac{d}{2}$

Then,

Put the value of d into the above formula:

Then,

$\begin{gathered} r=\frac{d}{2} \\ r=\frac{4}{2} \\ r=2m \end{gathered}$

Now,

According to the question:

The value of height is triple the radius.

So,

The length is:

$l=8$

Now,

From the formula of volume of the cylinder:

$\begin{gathered} V=\pi r^2h \\ V=3.14\times2^2\times8 \\ V=3.14\times4\times8 \end{gathered}$

Then,

$\begin{gathered} V=3.14\times32 \\ V=100.48 \end{gathered}$

Final answer:

Hence, the correct option is D.