Question

Twice a number decreased by 2 is 14

Answer 1

To solve this problem, first we need to define that the number is "x".

Then, we define what twice that number is, which would be

$2x$

We decrease that 2x by 2:

$2x-2$

And this would be equal to 14:

$2x-2=14$

That would be the equation that represents the problem.

To solve that equation...

We add +2 to both sides of the equation:

$\begin{gathered} 2x-2+2=14+2 \\ 2x=16 \end{gathered}$

and we divide both sides by 2:

$\begin{gathered} \frac{2x}{2}=\frac{16}{2} \\ x=8 \end{gathered}$

Answer:

the equation is: 2x - 2 = 14

and the value of x is: x =8