Question

Y= x^4-2x^3-8x^2+12x-16

Answer 1

$Y=x^4-2x^3-8x^2+12x-16$

We will simplify further:

$\begin{gathered} Y=x^4-2x^3-8x^2+12x-16 \\ when\colon x=0 \\ Y=0^4-2(0)^3-8(0^2+12(0)-16 \\ Y=-16 \\ \end{gathered}$