Question

15b^2 + 4b - 4 =0 factorize

Answer 1

A Quadratic equation can have the form:

$ax^2+bx+c=0$

Where "a" is the Leading coefficient.

In this case, you have the following Quadratic equation:

$15b^2+4b-4=0$

You can rewrite it as following:

$15x^2+4x-4=0$

The steps to factorize it are shown below:

1. Use the Quadratic formula:

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

2. You can see that:

$\begin{gathered} a=15 \\ b=4 \\ c=-4 \end{gathered}$

3. Substitute values into the Quadratic formula and evaluate:

$\begin{gathered} x=\frac{-4\pm\sqrt[]{4^2-4(15)(-4)}}{2(15)} \\ \\ x_1=\frac{2}{5} \\ \\ x_2=-\frac{2}{3} \end{gathered}$

4. Substituting the variable "x" by the variable "b", you can write it in the following factor form:

$15(b-\frac{2}{5})(b+\frac{2}{3})=0$

The answer is:

$15(b-\frac{2}{5})(b+\frac{2}{3})=0$