Question

approximate value of the square root of 48 rounded to the nearest tenth.

Answer 1

Given

$\sqrt[]{48}$

This can be found as shown below:

$\begin{gathered} \sqrt[]{48} \\ =\sqrt[]{16\times3} \\ =\sqrt[]{16}\times\sqrt[]{3} \\ =4\sqrt[]{3} \end{gathered}$

Let us check for root 3 from the square root table

$\sqrt[]{3}=1.732$

Therefore,

$\begin{gathered} 4\sqrt[]{3} \\ =4\times1.732 \\ =6.928 \\ \approx6.9(nearest\text{ tenth)} \end{gathered}$

Hence, the square root of 48 to the nearest tenth is 6.9