Given the parabola equation as,
[tex]y=x^2+16x+64[/tex]we know that, x coordinate of parabola is given as,
[tex]\begin{gathered} x=\frac{-b}{2a} \\ x=\frac{-16}{2\times1} \\ x=\frac{-16}{2} \\ x=-8 \end{gathered}[/tex]So, y coordinate by putting value of x in equation as,
[tex]\begin{gathered} y=x^2+16x+64 \\ y=(-8)^2+16(-8)+64 \\ y=64-128+64 \\ y=128-128 \\ y=0 \end{gathered}[/tex]Hence, the vertex for parabola is given as,
[tex](-8,0)[/tex]