Question

Find the area of the irregular figure. Round your answer to the nearest tenth. * 6 Et 12 Et O 92.5 ft 0 149.1 ft? O 128.5 ft2 185.1 ft?

Answer 1

Given an irregular figure.

The figure consists of a right triangle and a semi-circle

The triangle has a base = b = 12 ft

And a height = h = 6 ft

Area of the triangle =

$\frac{1}{2}bh=\frac{1}{2}\cdot12\cdot6=36ft^2$

The semi-circle has a radius = r = 6 ft

The area of the semi-circle =

$\frac{1}{2}\cdot\pi\cdot r^2=\frac{1}{2}\cdot3.14\cdot6^2=\frac{1}{2}\cdot3.14\cdot36=56.52ft^2$

So, the total area =

$36+56.52=92.52$

Rounding to the nearest tenth

So, the answer will be area = 92.5 ft^2