Step 1: We have two consecutive odd integers:
x = Lesser odd integer
x + 2 = Greater odd integer
Step 2: Let's write the equation to solve for x, this way:
107 more than the lesser is six times the greater
107 + x = 6 (x + 2)
107 + x = 6x + 12
Like terms:
x - 6x = 12 - 107
-5x = - 95
Dividing by -5 at both sides:
-5x/-5 = -95/-5
x = 19, therefore x + 2 = 19 + 2 = 21
Step 3: The correct answer is that the lesser consecutive odd integer is 19, and the greater consecutive odd integer is 21.
