Respuesta :

The boundary line is 2x+2y=-6.

The inequality can be either of th etwo,

[tex]2x+2y\leq-6,2x+2y\ge-6[/tex]

Since the portion contaims (0,0).

Putting it in both the inequality ,

we have,

[tex]2\times0+2\times0\leq-6\Rightarrow0\leq-6[/tex]

This is not possible . So we reject the first inequality.

Again,

[tex]2\times0+2\times0\ge-6\Rightarrow0\ge-6[/tex]

This is possible.

Thus the required inequality is,

[tex]2x+2y\ge-6[/tex]