Question

A zoo built an outdoor enclosure for gorillas next to the gorilla house. A scale drawing of the enclosure is shown above. What is the perimeter of the enclosure?A. 48 ftB. 140 ftC. 675 ftD. 720 ft

Answer 1

First, consider that the length of one side of each little square is l = 15 ft.

Next, consider that each side of the given figure has the following number of squares:

l1 = 7 squares

l2 = 15 squares

l3 = 10 squares

l4 = 5 squares

l5 = 3 squares

l6 = 10 squares

The perimeter of the figure is the sum of the length of one side of each square, then, for each square you have one side to contribute to the perimeter of the figure.

Then, you have the following equivalence:

1 square = 1 side = 15ft

And the perimeter is:

P = l1 + l2 + l3 + l4 + l5 + l6

P = 7 + 15 + 10 + 5 + 3 + 10

P = 50

each square equals to 15 ft in the actual length, then:

P = 50(15 ft)

P = 750 ft

Hence, the perimeter of the figure is 750 ft