A student's course grade is based on one midterm that counts as5% of his final grade, one class project that counts as 15% of his final grade, a set of homework assignments that counts as 50% of his final grade, and a final exam that counts as 30% of his final grade. His midterm score is 66, his project score is 84, his homework score is 83, and his final exam score is 68.What is his overall final score? What letter grade did he earn (A, B, C, D, or F)? Assume that a mean of 90 or above is an A, a mean of at least 80 but less than 90 is a B, and so on.His overall final score is ___ (Type an integer or decimal. Do not round.)His letter grade is ____

A students course grade is based on one midterm that counts as5 of his final grade one class project that counts as 15 of his final grade a set of homework assi class=

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Answer:

Given in the question:

The midterm counts as

[tex]\begin{gathered} 5\% \\ of\text{ his final grade} \end{gathered}[/tex]

Hence,

The score gotten from his midterm will be

[tex]\begin{gathered} =\frac{5}{100}\times66 \\ =\frac{330}{100} \\ =3.3\text{ out of 5} \end{gathered}[/tex]

The project score counts as

[tex]15\%[/tex]

Hence,

The score gotten from the project work from the weighted average will be

[tex]\begin{gathered} \frac{15}{100}\times84 \\ =12.6\text{ out of 15} \end{gathered}[/tex]

The homework assignments count as

[tex]50\%[/tex]

Hence,

The score gotten from the Homework from the weighted average will be

[tex]\begin{gathered} \frac{50}{100}\times83 \\ =41.5\text{ out of 50} \end{gathered}[/tex]

The exam counts as

[tex]30\%[/tex]

Hence,

The score gotten from the exam from the weighted average will be

[tex]\begin{gathered} \frac{30}{100}\times68 \\ =20.4\text{ out of 30} \end{gathered}[/tex]

The aggregate percentage will be given by

[tex]\begin{gathered} =3.3+12.6+41.5+20.4 \\ =77.8 \end{gathered}[/tex]

Hence,

His overall final score is

[tex]\Rightarrow77.8[/tex]

Therefore,

The student will rank at GRADE C because his score is greater than 70 but less than 80