The area of a circle is directly proportional to its diameter or radius, which means the larger the diameter/radius is, the larger will the area be.
In this case, Circle A has 5 inches of radius, and Circle B has 16 inches of diameter, but the radius is half the diameter, so Circle B actually has 8 inches of the radius.
Given that Circle B has a larger radius, we can deduct that it has a larger area.
Let's find each area.
[tex]\begin{gathered} A_a=\pi(5)^2=25\pi \\ A_b=\pi(8)^2=64\pi \end{gathered}[/tex]If we subtract, we find that Circle B is 39 square inches greater than Circle A.