Question

A ball is drawn randomly from a jar that contains 2 red balls, 8 white balls, and yellow balls. Findthe probability of the given event, and show your answers rounded to 4 decima places whenpossible,a. A red ball is drawn,P(red)b. A white ball is drawn.P(white)C. A yellow ball or red ball is drawn,P(yellow or red)

Answer 1

Explanation:

In the given question we would require the formula for probability to solve the questions. The formula is given below;

$Pr(Event)=\frac{number\text{ of favorable outcomes}}{\text{Total number of possible outcomes}}$

The total number of possible outcomes represents the number of balls in the jar. This is given below;

$2+8+4=14\text{ balls}$

Note: The number of favorable outcomes varies depending on the ball that would be picked

1) if a red ball is drawn, the number of favorable outcomes is 2 red balls

2)If a white ball is drawn, the number of favorable outcomes is 8 red balls

3) If a yellow ball is drawn, the number of favorable outcomes is 4 yellow balls

Also, the term "or" represents the union of two probabilities and can be represented by "+".

Workings:

Part A

The probability that a red ball is drawn is given as:

$Pr(\operatorname{Re}d)=\frac{2}{14}=\frac{1}{7}=0.1429$

Answer 1:

$Pr(red)=0.1429$

Part B

The probability that a white ball is drawn is given as;

$Pr(White)=\frac{8}{14}=0.5714$

Answer 2:

$Pr(White)=0.5714$

Part C

The probability that a yellow or red ball is drawn is given as

$Pr(\text{yellow or red)=}\frac{4}{14}+\frac{2}{14}=\frac{4+2}{14}=\frac{6}{14}=0.4286$

Answer 3:

$Pr(\text{yellow or white)}=0.4286$