Question

A geneticist conducts an experiment with beans, one sample of offspring consisted of 474 green beans and 143 yellow beans. Based on these results, estimate the probability of getting an offspring bean that is green.Report the answer as a percent rounded to one decimal place accuracy. I came up with Is the result reasonably close to the value of (fraction 3/4)3___4 that was expected?Can you confirm if this is correct? Yes or no?

Answer 1

Given: 474 green beans, and 143 yellow beans.

The probability of getting an offspring that is green is

$\begin{gathered} \Pr (\text{green beans})=\frac{\text{number of green beans}}{\text{total number of beans}} \\ \Pr (\text{green beans})=\frac{474}{474+143} \\ \Pr (\text{green beans})=\frac{474}{617}\approx0.768 \\ \\ \text{Converted to percentage that is} \\ \Pr (\text{green beans})=76.8\% \end{gathered}$