Respuesta :

Solution:

Given the equation:

[tex]3(5-4x)=3(3x+4)[/tex]

To solve,

Step 1: Open parentheses.

[tex]\begin{gathered} 3(5-4x)=3(3x+4) \\ \Rightarrow(3\times5)+(3\times-4x)=(3\times3x)+(3\times4) \\ \Rightarrow15+(-12x)=9x+12 \\ \Rightarrow15-12x=9x+12 \end{gathered}[/tex]

Step 2: Collect like terms.

[tex]\begin{gathered} -12x-9x=12-15 \\ \Rightarrow-21x=-3 \\ divide\text{ both sides by the coefficient of x, which is -21} \\ -\frac{21x}{-21}=-\frac{3}{-21} \\ \Rightarrow x=\frac{1}{7} \end{gathered}[/tex]

Hence, we have

[tex]x=\frac{1}{7}[/tex]