Question

V5Two lines are graphed on the coordinate plane below.Graphical Representation:If a point is a solution to an equation, thenthe point will be on the graph of theequation.Algebraic Representation:If a point is a solution to an equation, thensubstituting the values for x and y into theequation will produce a true statement.Line 2:Line 1: y.-26.4Consider the point A(3, 4).Is the point a solution to the equation for Line 1?nothe point isnt in the lineUse an algebraic representation

Answer 1

Let:

$\begin{gathered} y=\frac{1}{3}x-3 \\ y=-2x+4 \end{gathered}$$A(3,4)=(x,y)$

Let's evaluate the point into the line 1:

$\begin{gathered} x=3,y=4 \\ 4=\frac{1}{3}(3)-3 \\ 4=1-3 \\ 4=-2 \\ False \end{gathered}$

Therefore, the point is not on the line 1.

The algebraic representation is:

$4=\frac{1}{3}\cdot3-3$

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Let's evaluate the point into the line 2:

$\begin{gathered} x=3,y=4 \\ y=-2x+4 \\ 4=-2(3)+4 \\ 4=-6+4 \\ 4=-2 \\ False \end{gathered}$

Therefore, the point is not on the line 2.

The algebraic representation is:

$4=-2\cdot3+4$

The point is not a solution for both equations