Write the following in the intercept form;
[tex]6x-3y=-18[/tex]To express in intercept form, we need to express the equation based on the intercept with both axes.
The equation of a line in intercept form is shown as follows;
[tex]\begin{gathered} \frac{x}{a}+\frac{y}{b}=1 \\ a=x-intercept \\ b=y-\text{intercept} \\ To\text{ calculate the x and y intercepts;} \\ \text{When x=0} \\ 6(0)-3y=-18 \\ -3y=-18 \\ y=\frac{-18}{-3} \\ y=6 \\ \text{When y=0,} \\ 6x-3(0)=-18 \\ 6x=-18 \\ x=\frac{-18}{6} \\ x=-3 \\ \text{The y-intercept is 6, and the x-intercept is -3} \\ \text{Therefore, you now have} \\ \frac{x}{-3}+\frac{y}{6}=1 \end{gathered}[/tex]