In table A, there are two pairs of points. These are (3, -5) and (4, 9) and they formed a straight line. To determine the equation of the straight line using two points, we can use the formula below.
[tex]y-y_1=\frac{y_2-y_{1_{}}}{x_2-x_1}(x-x_1)[/tex]
Our (x₁, y₁) will be (3, -5).
Our (x₂, y₂) will be (4, 9).
Let's use these points to the formula above.
[tex]\begin{gathered} (y--5)=\frac{9--5}{4-3}(x-3) \\ y+5=\frac{14}{1}(x-3) \\ y+5=14x-42 \\ y=14x-42-5 \\ y=14x-47 \end{gathered}[/tex]
The equation of the line in slope-intercept form is y = 14x - 47.
The equation of the line in standard form is 14x - y = 47.
Description: This means that for every value of y, it is 14 times the value of x less 47.
