Question

Find the probability that when a single card is drawn from a regular deck of cards, a diamond or sixis chosen.a. 17/ 52b. 1/ 52c. 4/13d. none of the above

Answer 1

A normal deck of cards has 52 cards, so we know that the total of possibilities is 52.

Now we have to know that the same 52 cards have 4 suits: hearts, clubs, spades, and diamonds. Each suite has 13 cards.

Already, for each sub, we have the same numbers ace, 2, 3, 4,5, 6 ...

That means that we have a probability to draw a diamond of 13/52

And we have a probability to draw a 6 out of 4/52

But remember that exist 1 card which is a diamond 6 so,

Now sum the probabilities:

$P=\frac{13}{52}+\frac{4}{52}-\frac{1}{52}$

I subtract 1/52 because the diamond six has already been counted so the answer is

$P=\text{ }\frac{16}{52}$

ANS: d. none of the above.