Question

I was wondering if my answer of 0% was correct

Answer 1

To answer this question we need to do the proper punnet square.

Alleles

Fawn: f

Less curled tail: T

Tight tail: t

Parental cross: ffTT x fftt

Gametes:

$f\begin{cases}T=fT \\ T=fT\end{cases}f\begin{cases}t=ft \\ t=ft\end{cases}$

Punnet square

Phenotypic and genotypic frequencies

As we can see all the offspring obtained has the same genotype ffTt, therefore our genotypic and phenotypic frequencies are equal

fawn less curled tail ffTt: 16:16 = 16/16 = 1

So there is no possibility that a puppy with fawn hair and tight curl be born, the probability is 0%