Respuesta :
From the question, we were told that about 6% of the general population has a genetic mutation.
So, if we take a random sample of 600 people, about 6% of those 600 people will have that mutation.
(a) Find the mean.
To find the mean, recall:
Percentage = 6% = 0.06
Group size = 600
Mean (x) = Group size * percentage
Mean (x) = 600 * 0.06
Mean (x) = 36
(b) Standard deviation (o)
To find the Standard deviation, we use the formular:
[tex]\begin{gathered} S\text{ = }\sqrt{n}\left(p\right)\left(1-p\right)\text{ } \\ Where\text{ n is the sample size, p is the probability.} \\ So, \\ S\text{ = }\sqrt{600}\text{ \lparen0.06\rparen\lparen1-0.06\rparen} \\ S\text{ = }\sqrt{600}\text{ \lparen0.06\rparen\lparen0.94\rparen} \\ S\text{ = 24.4949 \lparen0.06\rparen\lparen0.94\rparen} \\ S\text{ = 1.3815} \\ S\text{ = 1.382 \lparen rounded to 3 decimal places\rparen} \end{gathered}[/tex]
