Question

Two factory plants are making tv panels. Yesterday, plant A produced twice as many panels as plant B. Four percent of the panels from plant A and 3% of the panels from plant B were defective. How many panels did plant B produce, If the two plants together produced 770 defective panels?

Answer 1

Let "x" represent the number of tv panels produced by plant B.

If plant A produced twice as many as plant B, then "2x" represents the number of tv panels produced by plant A.

For plant A, 4% of the panels were defective, to determine an expression that represents the number of defective panels, you have to multiply the amount produced by plant A by 0.04:

$0.04\cdot2x=0.08x$

The expression "0.08x" represents the number of defective panels produced by plant A.

For plant B, 3% of the panels produced were defective, to obtain an expression that represents the number of defective panels, you have to multiply the production of plant B by 0.03:

$0.03\cdot x=0.03x$

The expression "0.03x" represents the number of defective panels produces by plant B.

Both plants together produced 770 defective panels, you can write this as:

$0.08x+0.03x=770$

From this equation, you can determine the value of x:

-Add both x-terms

$0.11x=770$

-Divide both sides by 0.11

$\begin{gathered} \frac{0.11x}{0.11}=\frac{770}{0.11} \\ x=7000 \end{gathered}$

x=7000 → So plant B produces 7000 tv panels.