Question

7. The entry fee for a charity event is $15 per pair of people. The fee can be paid in cash or by collecting and turning in soda can tabs. Every 10 tabs collected earns $0.01. Brian and Eva are collecting tabs to pay their entry fee. So far, Eva has collected 7,100 tabs and Brian has collected 1,300 tabs. What is the least number of tabs they must still collect in order to have enough to pay the entry fee? A 9,200 B. 8,400 c. 6,900 FEE D. 6,600

Answer 1

Let's begin by identifying key information given to us:

Entry fee = $15 /pair pf people

10 tabs = $0.01

Eva = 7,100 tabs

Brian = 1,300 tabs

The entry fee is $15 for a pair

We will convert this to tabs, we have:

$\begin{gathered} 10tabs= 0.01 \\ x=15 \\ \text{Cross multiply, we have:} \\ 0.01(x)=10\cdot(15) \\ 0.01x=150 \\ x=\frac{150}{0.01}=15,000 \\ x=15,000tabs \end{gathered}$

Eva & Brian have gathered a total of 8,400 tabs. The number of tabs they need to collect to meet their target is given by the diffence between 15,000 & 8,400

$\begin{gathered} =(15,000-8,400)_{}tabs \\ =6,600tabs \end{gathered}$

Therefore, D (6,600) is the correct answer