Solution:
Given Bismuth-210 has a half-life of about 4 days.
[tex]\begin{gathered} \text{ After 4 days, }\frac{1}{2}(390\text{ mg\rparen = 195mg will remain} \\ \end{gathered}[/tex][tex]After\text{ 8 days, }\frac{195mg}{2}=97.5mg\text{ will remain}[/tex]The answer is 97.5mg