Question

If f(x) = 3x + 3, g(x) = 6x + 6, and h (x) = 9 x^2 + 18x + 9, then (f+g)(-1)=

Answer 1

In order to find the value of (f+g)(-1), first let's find the composite function (f+g)(x):

$\begin{gathered} (f+g)(x)=f(x)+g(x)\\ \\ =3x+3+6x+6\\ \\ =9x+9 \end{gathered}$

Now, let's use x = -1 and calculate its value:

$(f+g)(-1)=9\cdot(-1)+9=-9+9=0$

Therefore the value of (f+g)(-1) is equal to 0.