Question

A circle is centered at (5,-3) and has a radius of 16.Complete the equation of the circle.=;.: 4:: 16:: (y - 3):: 256:: (x – 5):: (x + 5)2:: (y + 3)2

Answer 1

The equation of the circle centered at (h,k) with radius r is:

$(x-h)^2+(y-k)^2=r^2$

In this case, the center is (5, -3) and the radius is 16, then the equation is:

$\begin{gathered} (x-5)^2+(y-(-3))^2=16^2 \\ (x-5)^2+(y+3)^2=256 \end{gathered}$