Question

Given the function f(t)= -16t^2+24t and f(1.5)= 0How high is the ball after how many seconds?

Answer 1

Since t represents the time and f(t) the height above the ground, we need to substitute t=1.5 i nto the given function f(t),

$f(1.5)=-16(1.5^2)+24(1.5)$

which gives

$f(1.5)=-36+36=0$

This means that the ball hits the ground after 1.5 seconds. Therefore, the answer is: The ball is 0 feet above the ground after 1.5 seconds