Question

fill in the blanks so the left side is a perfect square trinomial. That is, complete the square

Answer 1

Given the equation;

$x^2+4x+\text{?}=(x+\text{?)}^2$

We shall first express the equation in the form;

$\begin{gathered} a^2+2ab+b^2 \\ \text{Where,} \\ x=a,4x=2ab \\ \text{Therefore, } \\ 2ab=2\times2\times x(4x) \\ \text{When, } \\ 2a=2x,\text{ } \\ \text{Then,} \\ 2ab=2x(2)=4x \\ b=2 \\ \text{Hence, we now have;} \\ \\ x^2+4x+4=(x+2)^2 \end{gathered}$

ANSWER:

Left blank = 4

Right blank = 2