Question

a box is sliding down a ramp attains a velocity of 30 m/s in 3 seconds fron rest. what is the acceleration of the box?

Answer 1

Answer:

The acceleration of the box is;

$a=10m/s^2$

Explanation:

Given;

Final velocity v = 30 m/s

initial velocity u = 0

time taken t = 3 seconds

Acceleration is the change in velocity per unit time.

The acceleration a can be calculated using the formula;

$a=\frac{v-u}{t}$

substituting the given values we have;

$\begin{gathered} a=\frac{30-0}{3} \\ a=\frac{30}{3} \\ a=10m/s^2 \end{gathered}$

The acceleration of the box is;

$a=10m/s^2$