Question

what is the electric feild strength 5.0 cm from 6.6muC charge?(answer with two sig figs. For scientific notation answer like 2.3E-4.)

Answer 1

Given data

*The given distance is r = 5.0 cm = 0.05 m

*The given charge is

$q=6.6\mu C=6.6\times10^{-6}\text{ C}$

The formula for the electric field strength is given as

$E=\frac{kq}{r}$

*Here k is the Coulomb constant

Substitute the values in the above expression as

$\begin{gathered} E=\frac{(9\times10^9)(6.6\times10^{-6})}{0.05} \\ =1.18\times10^6\text{ N/C} \end{gathered}$