Given that mass of the ball is m = 2kg.
The energy of the ball is at the position I is E = 120 J.
The acceleration due to gravity is g = 9.8 m/s^2
A) We have to find the height of the object, h.
The height can be calculated as
[tex]\begin{gathered} E=mgh \\ h=\frac{E}{mg}\text{ } \\ =\frac{120}{2\times9.8} \\ =6.12\text{ m} \end{gathered}[/tex]
Thus, the height at the position I is 6.12 m
When the ball is traveling towards the ground from a height, the potential energy gets converted into kinetic energy until it reaches the ground.
B) It has potential energy as it is above the ground at a certain height and kinetic energy due to its motion.
Thus, at position II, the ball has the sum of kinetic and potential energy.
C) When the ball reaches position III, the potential energy gets converted into kinetic energy, increasing the velocity of the ball.
