Question

Find the slope and a point on the line 1 y-9=-1/3 (x - 4)

Answer 1

we have the following:

$y-9=-\frac{1}{3}(x-4)$

we reduce the equation to the following form:

$y=mx+b$

where, m is the slope, now

$\begin{gathered} y=-\frac{1}{3}x+\frac{4}{3}+9 \\ y=-\frac{1}{3}x+\frac{31}{3} \end{gathered}$

therefore, the slope is -1/3

the point:

$\begin{gathered} x=0 \\ y=-\frac{1}{3}\cdot0+\frac{31}{3} \\ y=\frac{31}{3} \end{gathered}$

the point is (0, 31/3)