Suppose that $2000 is placed in an account that pays 12% interest compounded each year.Assume that no withdrawals are made from the account.Follow the instructions below. Do not do any rounding.

Suppose that 2000 is placed in an account that pays 12 interest compounded each yearAssume that no withdrawals are made from the accountFollow the instructions class=

Respuesta :

Given:

Principal amount = $2000

Interest rate = 12%

Find-:

(a) Amount in an account at the end of 1 year

(b)Amount in an account at the end of 2 year

Sol:

Compounded interest rate is:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

(a)

Amount after 1 year is:

[tex]\begin{gathered} t=1 \\ \\ r=\frac{12}{100} \\ \\ r=0.12 \\ \\ n=1 \\ \\ P=2000 \end{gathered}[/tex]

So the amount is:

[tex]\begin{gathered} A=2000(1+\frac{0.12}{1})^{1\times1} \\ \\ A=2000(1.12) \\ \\ A=2240 \end{gathered}[/tex]

After one year amount in the account is $2240

(b)

Amount after two years is:

[tex]\begin{gathered} t=2 \\ \\ n=1 \\ \\ r=0.12 \\ \\ P=2000 \end{gathered}[/tex]

So amount is:

[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \\ A=2000(1+\frac{0.12}{1})^{1\times2} \\ \\ A=2000(1.12)^2 \\ \\ A=2000\times1.2544 \\ \\ A=2508.8 \end{gathered}[/tex]

After two years amount in the account is $2508.8