Question

Pre calc, question 1, bad work sorry if I don’t respond quickly.

Answer 1

Given:

$f(x)=_{}x^6-2x^2+3$$\begin{gathered} f(-x)=(-x)^6-2(-x)^2+3 \\ f(-x)=x^6-2x^2+3 \end{gathered}$$f(x)=f(-x)$

f is an even function.

Even function symmetric with respect to y-axis.

b)

$f(x)=x^3-5$$\begin{gathered} f(-x)=(-x)^3-5 \\ f(x)=-x^3-5 \end{gathered}$

function is neither odd nor even.

Its not symmetric.