Question

If Corey has 2 times as many nickels as dimes and they have a combined value of 80 cents, how many of each coin does he have? dimes nickels

Answer 1

Given:

Corey has 2 times as many nickels as dimes

Let the number of nickels = x

Let the number of dimes = y

So,

$x=2y$

and they have a combined value of 80 cents

$5x+10y=80$

Substitute from x = 2y

so,

$\begin{gathered} 5\cdot2y+10y=80 \\ 10y+10y=80 \\ 20y=80 \\ y=\frac{80}{20}=4 \\ x=2y=8 \end{gathered}$

so, the answer wil be:

dimes = 4

nickels = 8