Given two parallel lines, and two points on one of the lines
To Determine: The slope of the given line, and the graph of the perpendicular line to the given line
Solution:
From the given line, two points on the first line are
[tex]\begin{gathered} A(2,9) \\ B(-2,6) \end{gathered}[/tex]
The slope of any given line with two points is calculated using the formula below:
[tex]\begin{gathered} (x_1,y_1);(x_2,y_2) \\ s=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]
Using the two given points, the slope of the given line would be
[tex]\begin{gathered} s=\frac{6-9}{-2-2} \\ s=\frac{-3}{-4} \\ s=\frac{3}{4} \end{gathered}[/tex]
Hence, the slope of the given line is 3/4
Note that the slope of a perpendicular line to any given line is the negative inverse of the given line.
If s is the slope of the given line and m is the slope of the perpendicular line
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